4s^2-4s+1=225

Solution for 4s^2-4s+1=225 equation:

4s^2-4s+1=225

We move all terms to the left:

4s^2-4s+1-(225)=0

We add all the numbers together, and all the variables

4s^2-4s-224=0

a = 4; b = -4; c = -224;
Δ = b2-4ac
Δ = -42-4·4·(-224)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-60}{2*4}=\frac{-56}{8}
=-7
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+60}{2*4}=\frac{64}{8}
=8
$